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An object has a coefficient of kinetic friction of 0.2 and a normal force of 30N. Find the force of kinetic friction.

Respuesta :

Lanuel

Answer:

Force of kinetic friction, Fk = 6N

Explanation:

Given the following data;

Coefficient of kinetic friction, μ = 0.2

Normal force, Fn=30N

To find the Force of kinetic friction;

Mathematically, the force of kinetic friction is given by the formula;

Fk = μFn

Where;

  • Fk represents the force of kinetic friction.
  • μ represents the coefficient of friction.
  • Fn represents the normal force.

Substituting into the equation, we have;

Fk = 0.2*30

Fk = 6N

Therefore, the force of kinetic friction is 6N.

A force that is present between two moving objects or surfaces is called kinetic friction. It is estimated in newtons (N) and is calculated by:

[tex]\rm F_{k} =\rm \mu _{\rm k} F_{n}[/tex]

Where, [tex]\rm F_{k}[/tex] = frictional force,  [tex]\mu _{\rm k}[/tex]  = coefficient, [tex]\rm F_{n}[/tex] = normal force.

The kinetic friction of the object is 6N.

The kinetic friction can be estimated as:

Given,

  • Coefficient of kinetic friction ([tex]\mu[/tex]) = 0.2

  • Normal force [tex]\rm F_{n}[/tex] = 30 N

Substituting values in the formula:

[tex]\rm F_{k} =\rm \mu _{\rm k} F_{n}[/tex]

[tex]\begin{aligned}\rm F_{k} &= 0.2 \times 30\\\\\rm F_{k} &= 6 \rm N\end{aligned}[/tex]

Therefore, 6N is the frictional force.

To learn more about frictional force follow the link:

https://brainly.com/question/1714663