7.91 grams of methane gas occupy a volume of 11.2 liters at STP.
What is STP?
Standard temperature and pressure, abbreviated STP, refers to nominal conditions in the atmosphere at sea level.
First, we need to calculate the number of moles:
STP is 0 °C and 1 bar.
One mole of a gas at STP has a volume of 22.71 L .
Moles of CH₄ = 11.2 L × ([tex]\frac{1 mol}{22.71 L}[/tex])
Moles of CH₄ = 0.4932 mol
Now we will calculate the mass of CH₄
Moles = [tex]\frac{mass}{molar \;mass}\\[/tex]
Mass of CH₄ = 0.4932 × 16.03
Mass of CH₄ = 7.91 g
Hence, 7.91 grams of methane gas occupy a volume of 11.2 liters at STP.
Learn more about the STP here:
https://brainly.com/question/21207220
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