contestada

In ΔBCD, the measure of ∠D=90°, BC = 81 feet, and DB = 52 feet. Find the measure of ∠C to the nearest tenth of a degree.

Respuesta :

xenia168

Answer:

39.9°

Step-by-step explanation:

m∠C = β

sin β = [tex]\frac{52}{81}[/tex] ⇒ β = arcsin [tex]\frac{52}{81}[/tex] ≈ 39.9°

Answer:

39.9

Step-by-step explanation:

sinC=  

sin C = \{52}{81}

sinC=  

81

52

​  

 

C=\sin^{-1}{52}{81})

C=sin  −1 (  81 /52 )

C=39.9393\ 39.9^

C=39.9393≈39.9∘

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