Isaac's favorite cereal is running a promotion that says 1-in-4 boxes of the cereal contains a prize. Suppose that Isaac is going to buy 6 boxes of this cereal, and let X represent the number of prizes he wins in these boxes. Assume that these boxes represent a random sample, and assume that prizes are independent between boxes. What is the probability that he wins exactly 2 prizes in the 6 boxes?

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Answer: 0.3 on khan academy

Step-by-step explanation: ‍♂️

The probability that he wins exactly 2 prizes in the 6 boxes is to be considered as the 0.30.

Calculation of the probability:

Since Isaac's favorite cereal is running a promotion that says 1-in-4 boxes of the cereal contains a prize this mean

So,

P(box containing prize) = 1/4 = p  =0.25

So,

q=1 - p

= 0.75

And total box (n)=6

Let us assume x be number of prize win.

So,

Probability that he will win exactly two prize is

P(X=2)=  [tex]\binom {6}{2}(0.25)^2(0.75)^4[/tex]

= 0.2966

=0.30(approx)

hence, The probability that he wins exactly 2 prizes in the 6 boxes is to be considered as the 0.30.

Learn more about probability here: https://brainly.com/question/24760080