Answer:
[tex]\boxed {\boxed {\sf y= 2x-12}}[/tex]
Step-by-step explanation:
We are given a slope and a point, so we can use the point-slope equation.
[tex]y-y_1=m(x-x_1)[/tex]
where m is the slope and (x₁, y₁) is the point.
The slope is 2 and the point is (3,-6).
[tex]m= 2\\x_1=3 \\y_1=-6[/tex]
Substitute the values into the formula.
[tex]y--6=2(x-3)[/tex]
[tex]y+6=2(x-3)[/tex]
Distribute the 2 on the right side of the equation.
[tex]y+6=(2*x)+(2*-3)[/tex]
[tex]y+6=2x-6[/tex]
We want to get the line into the form: y=mx+b. We have to isolate y on one side of the equation. 6 is being added to y. The inverse of addition is subtraction; subtract 6 from both sides of the equation.
[tex]y+6-6=2x-6-6[/tex]
[tex]y=2x-6-6[/tex]
[tex]y=2x-12[/tex]
The line is y=2x-12 (slope=2 and y-intercept=-12)
