solve the following quadratic equation for all value of c i'm simplest form
5(x-2)^2=20

Answer:
x=-2 and x=0
Step-by-step explanation:
5(x-2)^2 = 20; divide by 5 both sides
(x-2)^2 = 4; take the square root of both sides
(x-2) = ±2, now set it equal to positive 2 and negative 2
x-2 = 2
x=4
AND
x-2 = -2
x=0
Answer:
The values of x is 0 and 4.
Step-by-step explanation:
You have to divide 5 by both sides;
[tex]5 {(x - 2)}^{2} = 20[/tex]
[tex] {(x - 2)}^{2} = 4[/tex]
You have to expand the brackets;
[tex] {x}^{2} - 4x +4 = 4[/tex]
[tex] {x}^{2} - 4 x = 0[/tex]
You have to factorize;
[tex]x(x - 4) = 0[/tex]
Lastly, you have to solve it;
[tex]x = 0[/tex]
[tex]x = 4[/tex]