Answer:
Solving the equation [tex]\frac{a^2-b^2}{2+d^3}[/tex] by putting a=6, b=4 and d=1/2 we get [tex]\frac{160}{17}[/tex]
Step-by-step explanation:
We are given formula: [tex]\frac{a^2-b^2}{2+d^3}[/tex]
and values a=6, b=4 and d=1/2
We need to put the values of a, b and d in the given equation [tex]\frac{a^2-b^2}{2+d^3}[/tex] and find their result
Putting values in the equation:
[tex]\frac{a^2-b^2}{2+d^3}\\=\frac{(6)^2-(4)^2}{2+(\frac{1}{2})^3}\\=\frac{36-16}{2+\frac{1}{8}}\\=\frac{20}{\frac{2*8+1}{8}}\\=\frac{20}{\frac{17}{8}}\\=\frac{20*8}{17}\\=\frac{160}{17}[/tex]
So, solving the equation [tex]\frac{a^2-b^2}{2+d^3}[/tex] by putting a=6, b=4 and d=1/2 we get [tex]\frac{160}{17}[/tex]
