Answer:
[tex]the \: required \: work is \to \\ \boxed{w = 147.3 \: J}[/tex]
Explanation:
[tex]the \: required \: force \: is \: the \: horizonal \: component \: of \: \\ the \: force \: f_{x} = 52 \cos(52) = \boxed{32.014396716 \: N} \\ the \: work \: to \: be \: done \: is \to \\ w = f \times s = 32.014396716 \times 4.6 \\ \boxed{w = 147.26622489 \: J}[/tex]
