The equation of the line perpendicular to the line y=-x+2 through the point (3,5) is y = x + 2
A linear equation is in the form:
y = mx + b
where y, x are variables, m is the rate of change and b is the initial value of y.
Two lines are said to be perpendicular if the product of their slope is -1. That is the slope of one line is the negative inverse of the other line.
Given the line y = -x + 2. The slope of the line is -1.
The slope of a line perpendicular is 1 (negative inverse of -1).
Hence:
[tex]y-y_1=m(x-x_1)\\\\y-5=1(x-3)\\\\y=x+2[/tex]
The equation of the line perpendicular to the line y=-x+2 through the point (3,5) is y = x + 2
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