Solve this equation algebraically!!!

Answer:
See Explanation
Step-by-step explanation:
[tex]1 - \sqrt{x} \neq \: 0 \\ \\ \therefore \: 1 \neq \sqrt{x} \\ \\ {1}^{2} \neq ({ \sqrt{x}) }^{2} \\ \\ 1 \neq \: x \\ [/tex]
Hence, x will take values other than 1.