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Quadrilateral W X Y Z is shown. Diagonals are drawn from point W to point Y and from point Z to point X and intersect at point C. Line segments Z C and C X are congruent. The length of W C is 2 x + 5 and the length of C Y is 3 x + 2. In quadrilateral WXYZ, WC = 2x + 5 and CY = 3x + 2. What must x equal for quadrilateral WXYZ to be a parallelogram? x =

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MrRoyal

The value of x must be 3, for quadrilateral WXYZ to be a parallelogram

The given parameters are:

[tex]\mathbf{CY = 3x + 2}[/tex]

[tex]\mathbf{WC = 2x + 5}[/tex]

From the question, we understand that:

Segments ZC and CX are congruent

This means that:

Segments WC and CY are congruent

So, we have:

[tex]\mathbf{WC = CY}[/tex]

This gives

[tex]\mathbf{3x +2 = 2x + 5}[/tex]

Collect like terms

[tex]\mathbf{3x + 2x =-2 + 5}[/tex]

[tex]\mathbf{x =3}[/tex]

Hence, the value of x must be 3, for quadrilateral WXYZ to be a parallelogram

Read more about parallelograms at:

https://brainly.com/question/888539

sakshamisntgay

Answer:

Its 3

Step-by-step explanation:

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