Answer:
0.010g of C-14 would be later after 50,000 years
Explanation:
The kinetics of radioactive decay follows the equation:
Ln (N / N₀) = -kt
Where N could be taken as mass after time t,
N₀ initial mass = 4.30g;
k is rate constant = ln 2 / t(1/2)
= ln 2 / 5730years = 1.2097x10⁻⁴ years ⁻¹
Replacing:
Ln (N / 4.30g) = -1.2097x10⁻⁴ years ⁻¹ * 50000 years
N / 4.30 = 2.36x10⁻³
N =
0.010g of C-14 would be later after 50,000 years
