Answer:
The time taken for the paint ball to hit the ground is [tex]t = 2.143 \ s[/tex]
The distance of the landing point from the tower is [tex]d = 192.86 \ m[/tex]
Explanation:
From the question we are told that
The height of the tower is [tex]h = 45 \ m[/tex]
The speed of the paintball in the horizontal direction is [tex]v_x = 90 \ m/s[/tex]
Generally from kinematic equation we have that
[tex]h = ut + \frac{1}{2} at^2[/tex]
Here u is the initial velocity of the paintball in the vertical direction and the value is 0 m/s , this because the ball was fired horizontally
a is equivalent to [tex]g = 9.8\ m/s^2[/tex]
t is the time taken for the paintball to hit the ground
So
[tex]45 = 0* t + \frac{1}{2} 9.8 * t^2[/tex]
=> [tex]t = 2.143 \ s[/tex]
Generally the distance of its landing position from the tower is
[tex]d = v * t[/tex]
=> [tex]d = 90 * 2.143[/tex]
=> [tex]d = 192.86 \ m[/tex]
