Respuesta :
Given:
The system of equations is
[tex]x+3y=42[/tex] ...(i)
[tex]2x-y=14[/tex] ...(ii)
To find:
The number that must be multiplied with the second equation to eliminate the y-variable.
Solution:
Coefficient of y variable in equation (i) is 3 and in equation (ii) is -1.
To eliminate y-variable the absolute value of coefficients of y-variables should be same.
So, we need to multiply the second equation by 3 to eliminate the y-variable
Multiplying equation (ii) by 3, we get
[tex]6x-3y=42[/tex] ...(iii)
Adding (i) and (iii), we get
[tex]x+3y+6x-3y=42+42[/tex]
[tex]7x=84[/tex]
Divide both sides by 7.
[tex]x=12[/tex]
Put x=12 in (i).
[tex]12+3y=42[/tex]
[tex]3y=42-12[/tex]
[tex]3y=30[/tex]
Divide both sides by 10.
[tex]y=10[/tex]
Therefore, x=12 and y=10.
Answer:
Multiply the second equation by 3. The solution is x = 12, y = 10.
Step-by-step explanation:
Took test on edmentum/plato
