Given :
A jogger runs 5.0 km on a straight trail at an angle of 60° south of west.
To Find :
The southern component of the run rounded to the nearest tenth of a kilometre.
Solution :
We know, southern component is given by :
[tex]d = Dsin \ \theta\\\\d = 5\times sin \ 60^{\circ}\\\\d = -4.33\ km[/tex]
Here, negative sign indicates south direction.
Therefore, the southern component of the run rounded to the nearest tenth of a kilometre is 4.3 km.
Hence, this is the required solution.
The southern component of the run in nearest tenth is 4.3 km.
The given parameters:
The southern component of the run is calculated by finding the equivalent vertical component of the distance covered by the runner as follows;
[tex]d_y = d \times sin(\theta)\\\\d_y = 5 \ km\times 60\\\\d_y = 4.3 \ km[/tex]
Thus, the southern component of the run in nearest tenth is 4.3 km.
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