Respuesta :
Answer: The empirical formula is [tex]C_3NH_5O[/tex].
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 50.69 g
Mass of N= 19.71 g
Mass of H = 7.09 g
Mass of O = 22.51 g
Step 1 : convert given masses into moles.
Moles of C = [tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{50.69g}{12g/mole}=4.22moles[/tex]
Moles of N=[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{19.71g}{14g/mole}=1.41moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{7.09g}{1g/mole}=7.09moles[/tex]
Moles of O = [tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{22.51g}{16g/mole}=1.41moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{4.22}{1.41}=3[/tex]
For N = [tex]\frac{1.41}{1.41}=1[/tex]
For H = [tex]\frac{7.09}{1.41}=5[/tex]
For O =[tex]\frac{1.41}{1.41}=1[/tex]
The ratio of C:N:H: O = 3:1:5:1
Hence the empirical formula is [tex]C_3NH_5O[/tex].
