Answer:
0.9962
Step-by-step explanation:
The objective of this question is to determine the proportion of average city temperature that is lower than that of Singapore.
Suppose X is a random variable that follows a normal distribution:
Then;
[tex]X \sim N ( \mu = 20.66, \sigma = 2)[/tex]
[tex]P(X< 26) = P \bigg ( Z < \dfrac{26 - 20.66}{2} \bigg)[/tex]
[tex]P(X< 26) = P \bigg ( Z < \dfrac{5.34}{2} \bigg)[/tex]
[tex]P(X< 26) = P \bigg ( Z < 2.67\bigg)[/tex]
From the z tables;
P(X< 26) = 0.9962
Thus, there is 0.9962 proportion of average city temperature are lower than that of Singapore.
Answer:
0.9962
Step-by-step explanation:
A set of average city temperatures in May are normally distributed with a mean of 20.66 degrees and a standard deviation of 2 degrees. The average temperature of Singapore is 26 degrees
What proportion of average city temperatures are lower than that of Singapore?
Solution:
The z score shows the number of standard deviations by which the raw score is above or below the mean. If the raw score is above the mean then the z score is positive but if the raw score is less than the mean then the raw score is negative. The z score is given by:
[tex]z=\frac{x-\mu}{\sigma}\\\\where\ x=raw\ score, \mu=mean,\sigma=standard\ deviation[/tex]
Given that μ = 20.66, σ = $2
For the average temperature of Singapore of 26°, the z score is:
[tex]z=\frac{x-\mu}{\sigma}=\frac{26-20.66}{2} =2.67[/tex]
From the normal distribution table, P(x < 26) = P(z < 2.67) = 0.9962
