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09-11-2020
Chemistry

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The solubility of gas in water at 25 C and 1.0 atm pressure of oxygen is 0.061 g/ L. What would the pressure be if the solubility of oxygen water at 25 C is 0.075 g/L

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09-11-2020

Answer:

P2 = 1.2265 atm (Approx)

Explanation:

Given:

Water temperature = 25 degree Celsius

Pressure = 1 atm

So,

P1/P2 = C1/C2

1 / P2 = 0.061 / 0.075

P2 = 1.2265 atm (Approx)

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