Respuesta :
Answer:
The radius of the circular loop is 0.233 m
Explanation:
Given;
current on the circular loop, I = 63 A
magnitude of the magnetic field, B = 1.7 x 10⁻⁴ T
The magnetic field at the center of a circular loop is given by;
[tex]B = \frac{\mu I}{2R} \\\\[/tex]
Where;
R is the radius of the circular loop
μ is the permeability of free space = 4π x 10⁻⁷ T.m/A
Substitute the givens;
[tex]B = \frac{\mu I}{2R}\\\\R = \frac{\mu I}{2B}\\\\R = \frac{(4\pi*10^{-7})(63) }{2(1.7*10^{-4})}\\\\R = 0.233 \ m[/tex]
Therefore, the radius of the circular loop is 0.233 m
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The radius of the circular loop is 0.233 m.
What is a magnetic field?
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.
As we know that current is directly propotional to the induced magnetic field greater the current I, the greater the magnetic field B.
The given data in the problem is;
I is the value of current = 63 A
B is the megnetic field = 1.70 10⁻⁴ T
r is the radius of loop=?
μ is the permeability of free space = 4π x 10⁻⁷ T.m/A
The value of the megnetic field at the center is given by;
[tex]\rm B= \frac{\mu I}{2r} \\\\ \rm r= \frac{\mu I}{2B} \\\\ \rm r= \frac{4\pi \times 63}{2\times 1.7\times 10^{-4}} \\\\ \ \rm r=0.233 m[/tex]
Hence the radius of the circular loop is 0.233 m.
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022
