You apply a potential difference of 4.50 V between the ends of a wire that is 2.50 m in length and 0.654 mm in radius. The resulting current through the wire is 17.6 A. What is the resistivity of the wire?

Respuesta :

Answer:

ρ = 1.37x10⁻⁷ Ωm

Explanation:

The resistivity, ρ, of a wire is defined as:

ρ = R*A / L

Where R is resistance:

V / i= R

4.50V / 17.6A = 0.2557Ω

A is the area of the cross-section:

πR²

π* (0.654x10⁻³m)²

A = 1.344x10⁻⁶m²

And L is length of the wire:

L = 2.50m.

Replacing:

ρ = 0.2557Ω*1.344x10⁻⁶m² / 2.50m

ρ = 1.37x10⁻⁷ Ωm