A student performed the experiment in this module but failed to follow the procedure exactly, keeping the crucible completely covered during the entire heating and cooling processes. Be specific.
1. Explain the probable effect of this procedural change on the experimental results.
2. Would the student's calculated percent water in the hydrate be high, low, or unaffected? Briefly explain

1. If a "container" (in this case a crucible) is closed throughout a heating experiment. Then it must be noted that water vapor will not be able to escape during the course of the experiment. The water vapor will form a "cloud" of water droplets under the cover of the crucible. And when this crucible is cooled, this water droplets return back to the content/substance inside the crucible.

2. When compared with the initial amount of water present in the substance in the crucible, the percentage of water "left" in the hydrate or substance in the crucible would be high. This is because the water vapor that was suppose to leave the crucible did not leave because the crucible was closed (thus causing very low amount of water vapour to leave).

mickymike92 mickymike92 · Answer 2 · 2022-03-18T16:27:01+01:00

Because of the student error, the percent water of crystallization value the hydrate will be lower than its actual value.

What is evaporation?

Evaporation is the process by which a liquid changes spontaneously to vapor.

In the experiment to determine percentage water of crystallization, the crucible is left open to ensure all the water molecules are removed by evaporation.

However,, since the student did not remove the crucible cover during heating, some water molecules will not be able to escape completely, but will return back to the salt.

Hence, the percent water of crystallization value the hydrate will be lower because the of mass of the anhydrous salt will be higher than its actual value.

Learn more about percent water of crystallization at: https://brainly.com/question/7805021