Answer:
Hw = 1.01 meters
Explanation:
Given data:
flow rate = 10 m^3
depth of flow in channel = 2 m
Determine the height of a suppressed rectangular weir ( Hw ) using the following expressions
expression for the elevation of of water surface above crest of weir
H = 2 - [tex]H_{w}[/tex] ------ ( 1 )
expression for the height of the weir ( Hw )
Hw = 2 - [tex]( \frac{Q}{C_{w} b}) ^{\frac{3}{2} }[/tex] ---------- ( 2 )
expression for the weir coefficient ( Cw )
Cw = [tex]\frac{2}{3} C_{d} \sqrt{2g}[/tex] -------------- ( 3 )
expression for the coefficient of discharge ( Cd )
Cd = 0.611 + 0.075 [tex]\frac{H}{Hw}[/tex] ---------- ( 4 )
Finally to determine the value of Hw we apply the trial and error method
in the trial and error method the value of LHS = RHS for the number chosen to be true
