Answer:
The athlete's tangential velocity is 0.88 m/s.
Step-by-step explanation:
We have that the athlete completes 4 laps around a track with a radius of 25 meters in 12 minutes:
[tex] \omega = \frac{\theta}{t} [/tex]
Where:
ω: is the angular speed
θ: is the angular displacement
t: is the time = 12 min = 720 s
The angular displacement is:
[tex] \theta = 4 rev*\frac{2\pi rad}{1 rev} = 25.13 rad [/tex]
Now, the angular speed is:
[tex] \omega = \frac{\theta}{t} = \frac{25.13 rad}{720 s} = 0.035 rad/s [/tex]
Finally, the athlete's tangential velocity is:
[tex] v = \omega r = 0.035 rad/s*25 m = 0.88 m/s [/tex]
Therefore, the athlete's tangential velocity is 0.88 m/s.
I hope it helps you!
