Answer:
337 °C
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 5.20 L
Initial pressure (P1) = 1.20 atm
Initial temperature (T1) = 32 °C
Final pressure (P2) = 6 atm
Final volume (V2) = 2.08 L
Final temperature (T2) =?
Next, we shall convert 32 °C to Kelvin temperature. This can be obtained as follow:
T (K) = T (°C) + 273
Initial temperature (T1) = 32 °C
Initial temperature (T1) = 32 °C + 273
Initial temperature (T1) = 307 K
Next, we shall determine the final temperature of the gas as illustrated below:
Initial volume (V1) = 5.20 L
Initial pressure (P1) = 1.20 atm
Initial temperature (T1) = 305 K
Final pressure (P2) = 6 atm
Final volume (V2) = 2.08 L
Final temperature (T2) =?
P1V1 /T1 = P2V2 /T2
1.2 × 5.2 / 305 = 6 × 2.08 / T2
Cross multiply
1.2 × 5.2 × T2 = 305 × 6 × 2.08
6.24 × T2 = 3806.7
Divide both side by 6.24
T2 = 3806.7 / 6.24
T2 = 610 K
Finally, we shall convert 610 K to celsius temperature. This can be obtained as follow:
T (°C) = T(K) – 273
T(K) = 610 K
T (°C) = 610 – 273
T (°C) = 337 °C
Thus, the final temperature of the gas is 337 °C.
