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Write the net ionic equation for the reaction that occurs when equal volumes of 0.080 M aqueous acetic acid and sodium nitrite are mixed. It is not necessary to include states such as (aq) or (s).

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Answer:

CH₃COO⁻ + NaNO₂ → CH₃COONa + NO₂⁻      

Explanation:

When equal volumes of 0.080 M aqueous acetic acid and sodium nitrite are mixed (1:1), we have:                            

Acetic acid = CH₃COOH    

Sodium nitrite = NaNO₂

The molecular equation is:              

CH₃COOH(aq) + NaNO₂(s) → CH₃COONa(s) + HNO₂(aq)      

The ionic equation is:

CH₃COO⁻H⁺ + Na⁺NO₂⁻  → CH₃COO⁻Na⁺ + H⁺NO₂⁻            

The net ionic equation is:          

CH₃COO⁻ + NaNO₂ → CH₃COONa + NO₂⁻      

I hope it helps you!                                  

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