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A 180 pound person is hanging onto a 15-foot rope. Assuming the rope is uniform and that it weighs 2 pound per foot, set up (but do not evaluate) the integral that would calculate the work required to pull the person up 15 feet. Explain what of the values in your expression represent by labeling each.

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Answer:

The answer is "g= 32 FPS"

Step-by-step explanation:

Given value:

[tex]mass = 180\\\\length= 15 \\\\\lambda = \frac{ mass}{ length} = 2 \ \text{pound per foot} \\\\\bold{Formula}\\\\ \to w \int_{a}^{b} F \cdot d \ dx = \int_{0}^{15} (2x+180) \ g \ dx[/tex]

by solving the value we get the value of g that is equal to 32.

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