Five times the second of three consecutive odd integers is thirteen less than three times the sum of the first and third integers. Find the largest odd number.

Question

contestada

Respuesta :

Аноним Аноним · Answer 1 · 2020-11-09T15:23:22+01:00

Answer: 15

Step-by-step explanation:

suppose; three consecutive odd integers are x; x + 2; x+ 4 (x is a odd integer)

because Five times the second of three consecutive odd integers is thirteen less than three times the sum of the first and third integers

=> 5(x + 2) = 3( x +x +4) - 13

<=> 5x + 10 = 6x + 12 - 13

<=>6x - 5x = 10 + 13 - 12

<=> x = 11

=> the largest odd number is 11 + 4 = 15

Answer Link

fichoh fichoh · Answer 2 · 2021-10-22T10:51:00+02:00

The largest of the three consecutive odd integers which could be written as a, a+2 and a + 4 is 15

Let the integers be : a, a + 2, a + 4

Creating a mathematical equation using the scenario given.

5(a + 2) = 3(a + (a + 4)) - 13

Open the bracket bracket

5a + 10 = 3(2a + 4) - 13

5a + 10 = 6a + 12 - 13

5a + 10 = 6a - 1

Collect like terms

5a - 6a = - 1 - 10

-a = - 11

a = 11

The largest integer = a + 4 ; 11 + 4 = 15

Therefore, the largest of the consecutive odd integers is 15

Learn more : https://brainly.com/question/18109354