Amourxmia Amourxmia

09-11-2020
Mathematics

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What is the conjugate of the denominator (5 – V2)?

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jimrgrant1 jimrgrant1

09-11-2020

Answer:

5 + [tex]\sqrt{2}[/tex]

Step-by-step explanation:

Given a ± [tex]\sqrt{b}[/tex] , then the conjugate is

a ∓ [tex]\sqrt{b}[/tex]

Given

5 - [tex]\sqrt{2}[/tex] , then the conjugate is 5 + [tex]\sqrt{2}[/tex]

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