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Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to
350 K. If the volume of the bottle remains constant, what is the pressure, in pascals,
inside the hot water bottle?

Respuesta :

Lanuel

Answer:

P2 = 128,205 pascal.

Explanation:

Given the following data;

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

[tex] PT = K[/tex]

Where;

  • P represents pressure.
  • T represents temperature.
  • K is the constant of proportionality.

[tex] \frac{P1}{T1} = \frac{P2}{T2}[/tex]

Making P2 as the subject formula, we have;

[tex] P_{2}= \frac{P1}{T1} * T_{2}[/tex]

Substituting into the equation, we have;

[tex] P_{2}= \frac{100000}{273} * 350[/tex]

[tex] P_{2}= 366.3004* 350[/tex]

P2 = 128205.13 ≈ 128205 pascal.

Therefore, the pressure inside the hot water bottle is 128,205 pascal.

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