Respuesta :
Answer:
The rate of change is y with respect to x is [tex]\frac{25}{4}[/tex]
Step-by-step explanation:
Given
[tex]25x - 4y = 50[/tex]
Required
Determine the rate of change of y w.r.t x
[tex]25x - 4y = 50[/tex]
First, make y subject of formula
[tex]4y = 25x- 50[/tex]
Divide through by 4
[tex]y = \frac{25x}{4} - \frac{50}{4}[/tex]
[tex]y = \frac{25x}{4} - 12.5[/tex]
Next, we differentiate the above w.r.t to x
The result of the differentiation is the solution to the question
[tex]y' = 1 * \frac{25x^{1-1}}{4} -0[/tex]
[tex]y' = 1 * \frac{25x^0}{4}[/tex]
[tex]y' = 1 * \frac{25*1}{4}[/tex]
[tex]y' = \frac{25}{4}[/tex]
Hence, the rate of change is y with respect to x is [tex]\frac{25}{4}[/tex]
By calculating derivative of y with respect to x we got rate of change of y with respect to x for 25x-4y=0 is 25/4
What is derivative?
Rate of change of a function with respect to a variable is called derivative of that function with respect to that variable .
Here given relation is 25x-4y=0
[tex]\Rightarrow 4y=25x\\\\\Rightarrow y=\frac{25x}{4}[/tex]
We have to calculate rate of change of y with respect to x so we will calculate derivative of y with respect to x.
we can calculate derivative of y with respect to x as
[tex]\frac{dy}{dx}= \frac{d}{dx} (\frac{25x}{4})\\\\[/tex]
As 25/4 is constant we can take it out from derivative function as it is
[tex]\frac{dy}{dx}= (\frac{25}{4})\frac{dx}{dx}\\\\[/tex]
And we know derivative of a variable with respect to itself is 1
so
[tex]\frac{dy}{dx}= (\frac{25}{4})\times 1\\\\ \frac{dy}{dx}= \frac{25}{4}[/tex]
By calculating derivative of y with respect to x we got rate of change of y with respect to x for 25x-4y=0 is 25/4
To learn more about derivative visit: https://brainly.com/question/25081524
