contestada

A force of 8.00 newtons acts on a block across a horizontal frictionless surface for 12.0
seconds.
The block travels 4.00 meters. What is the change in kinetic energy during these 12.0
seconds?

Respuesta :

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The required value of the change in kinetic energy during the given time interval is 32 J.

Given data:

The magnitude of force is, F = 8.00 N.

The time interval is,  t = 12.0 s.

The distance covered by the block is, s = 4.00 m.

Here we can easily obtain the required result by applying the Work - Energy theorem. As per the work - energy theorem, the work done due to the applied force is equal to the change in kinetic energy.

Therefore,

W = ΔKE

And the work done is, W = Fs.

F× s = ΔKE

8.00 × 4.00 =  ΔKE

ΔKE = 32 J

Thus, we can conclude that the required value of the change in kinetic energy during the given time interval is 32 J.

Learn more about the work energy theorem here:

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