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Triangle A B C is shown. Lines are drawn from each point to the opposite side and intersect at point D. They form line segments A G, B E, and C F.
In the diagram, which must be true for point D to be an orthocenter?

BE, CF, and AG are angle bisectors.
BE ⊥ AC, AG ⊥ BC, and CF ⊥ AB.
BE bisects AC, CF bisects AB, and AG bisects BC.
BE is a perpendicular bisector of AC, CF is a perpendicular bisector of AB, and AG is a perpendicular bisector of BC.

Respuesta :

Answer:

B BE⊥AC, CF ⊥AB

Step-by-step explanation:

on Edge

In the given triangle ABC, point D is orthocenter when BE ⊥ AC, AG ⊥ BC, and CF ⊥ AB.

What is an orthocenter of a triangle?

"The orthocenter is the point where all the three altitudes of the triangle cut or intersect each other."

In the given triangle ABC, to be an orthocenter, all three lines that are drawn from the points A, B, and C are must be perpendicular to the opposite side of the triangle.

Therefore,  AG must be perpendicular to BC, BE must be perpendicular to AC, and CF must be perpendicular to AB.

Learn more about the orthocenter of a triangle here: https://brainly.com/question/19763099

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