Answer:
Volume of hydrogen produced = 4.485 L
Explanation:
Given data:
Volume of hydrogen produced = ?
Pressure = standard = 1 atm
Temperature = standard = 273.15 K
Mass of Ni = 12.34 g
Solution:
Chemical equation:
2HClO₃ + Ni → Ni(ClO₃)₂ + H₂
Number of moles of Ni:
Number of moles = mass / molar mass
Number of moles = 12.34 g / 58.69 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of hydrogen with nickel.
Ni : H₂
1 : 1
0.2 : 0.2
Volume of hydrogen:
PV = nRT
1 atm × V = 0.2 mol × 0.0821 atm.L/mol.K × 273.15 K
V = 4.485 atm.L/1 atm
V = 4.485 L
