Respuesta :

[tex]\tt C.~Ka=\dfrac{[H^+][CN^-]}{[HCN]}[/tex]

Further explanation  

According to Arrhenius, acids are substances which, when dissolved in water, release Hions.  

An HₓY acid in water will ionize:  

HₓY (aq) ⇒ xH⁺ (aq) + Yˣ- (aq)  

In general, the weak acid ionization reaction  

HA (aq) ⇒ H⁺ (aq) + A⁻ (aq)  

Ka's value  

[tex]\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}[/tex]

So for HCN

HCN(aq)⇒H⁺(aq)+CN⁻(aq)

[tex]\tt Ka=\dfrac{[H^+][CN^-]}{[HCN]}[/tex]

Answer:

c

Explanation: