Answer:
The equation y = 16·x² is symmetrical about the line(/point) x = 0
Step-by-step explanation:
The given equation is y = 16·x²
The given data is presented as follows;
x [tex]{}[/tex] y
-4 256
-3 144
-2.5 100
-2 64
-1.5 36
-1 16
-0.5 4
0 0
0.5 4
1 16
1.5 36
2 64
2.5 100
3 144
4 256
The equation compared to the equation of a parabola in vertex form, y = a·(x - h)² + k
We have;
a = 16
The vertex of the parabola , (h, k) = (0, 0) and x = h = 0 gives the axis of symmetry
Therefore, the equation y = 16·x² is symmetrical about the line x = 0.
