Answer:
The climber moves 15 feet per hour.
Step-by-step explanation:
A rock climber's height, in feet, when climbing a shear wall can be expressed by the equation h=15t, where t is time measured in hours
h is distance and t is time.
[tex]\dfrac{h}{t}=15[/tex]
or
[tex]\dfrac{d}{t}=15[/tex]
Distance per unit time is equal to the velocity of an object.
velocity = 15 feet per socond
Hence, the climber moves 15 feet per hour.