The diagram shows two forces acting perpendicularly on an object. The forces have magnitudes F1 = 8.2 N and F2 = 20.6 N. What is the net force acting on the object?
a) magnitude 22 N; direction 68 degrees counterclockwise from
b) magnitude 22 N; direction 22° counterclockwise from
c) magnitude 25 N; direction 34° counterclockwise from
d) magnitude 25 N; direction 68° counterclockwise from

Respuesta :

Answer:

Option (b).

Explanation:

Two forces are acting perpendicularly on an object. We have, F₁ = 8.2 N and F₂ = 20.6 N

We need to find the net force acting on the object. When two forces are acting in perpendicular to each other, the net force on it is given by :

[tex]F=\sqrt{F_1^2+F_2^2} \\\\=\sqrt{8.2^2+20.6^2} \\\\=22.17\ N[/tex]

or

F = 22 N

Let [tex]\theta[/tex] is the angle. It can be given by :

[tex]\tan\theta=\dfrac{F_1}{F_2}\\\\\tan\theta=\dfrac{8.2}{20.6}\\\\=21.7^{\circ}[/tex]

or

[tex]\theta=22^{\circ}[/tex]

So, the net force is 22 N and the direction is 22° counterclockwise from F₁. Hence, the correct option is (b).