Beverley has quarters and dimes in her pocket. She has 21 coins with a total value of $3.00. How many of each type of coin does she have? [?] quarters [ dimes Enter the number that belongs in the green box. Enter

Answer:
Step-by-step explanation:
If all 21 coins were dimes, she'd have $2.10. But she has 90 more cents than that. Now for each coin that's a quarter, not a dime, she has 15 cents more. 90/15= 6. So there are 6 quarters, and 21-6 = 15 dimes.
Now we do it backwards to see if it's right. 6 quarters is $1.50, 15 dimes is $1.50, add those together and you get $3. So it's right. 6 quarters, 15 dimes.
Beverley has quarters and dimes in her pocket.
There are 15 dimes and 6 quarters in her pocket.
1 Dime = $ 0.1
1 Quarter = $0.25
Let there be "D" dimes and "Q" Quarters.
So according to the given situation as there are total 21 coins which can be formulated in equation (1)
[tex]\rm Q + D = 21 .......(1) \\[/tex]
Also the total value of money is $3 which can be formulated in equation (2)
[tex]\rm 0.1 D + 0.25 Q = 3 .............(2)[/tex]
Equations (1) and (2) represents two linear equations with two variables
On solving equation (1) and (2) for Q and D we can get
D = 15 and Q = 6
So we can conclude that there are 15 dimes and 6 quarters in Beverley's pocket.
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