if z is the circumcenter of triangle qrs find each measure

Answer:
Step-by-step explanation:
Circumcenter of A triangle is the center of a circle passing through the vertices of the given triangle.
So, the distance of Z from the vertices Q, R and S will be the radii of the circle.
Therefore, ZQ = ZR = ZS
Since, circumcenter of a triangle is defined by the point of intersection of the perpendicular bisectors of the sides of the given triangle.
Therefore, points W, X and Y are the midpoints of sides QR, RS and QS.
Using these facts,
a). QR = 2(WQ)
= 2(25)
= 50
b). Apply Pythagoras theorem in ΔRXZ,
(RZ)² = (RX)² + (ZX)²
(RZ)² = (40)² + (9)²
RZ = √1681 = 41
c). XS = [tex]\frac{1}{2}(RS)[/tex]
= [tex]\frac{1}{2}(80)[/tex]
= 40
d). Since, ZQ = ZR = ZS
ZS = 41
e). By applying Pythagoras theorem in ΔRWZ,
(RZ)² = (WZ)² + (WR)²
(41)² = (WZ)² + (25)²
(WZ)² = (41)² - (25)²
WZ = √1056
WZ = [tex]4\sqrt{66}[/tex]
≈ 32.5
Applying the circumcenter theorem and the Pythagorean Theorem, the following measures are calculated as:
a. QR = 50
b. RZ = 41
c. XS = 40
d. ZS = 41
e. WZ = 32.5
Based on the circumcenter theorem of a triangle, the following holds true given that Z is the circumcenter of triangle QRS:
Given:
a. Find QR:
QR = 2 × WQ = 2 × 25
QR = 50
b. Find RZ in right ΔXRZ:
XZ = 9 (given)
XR = 1/2(RS) = 1/2(80) = 40
RZ = √(XZ² + XR²)
RZ = √(9² + 40²)
RZ = 41
c. Find XS:
XS = 1/2(RS) = 1/2(80)
XS = 40
d. Find RZ:
RZ = ZS = QZ = 41 (equidistant)
ZS = 41
e. Find WZ in right ΔWRZ:
WR = WQ = 25
WR = 25
RZ = 41
WZ = √(RZ² - WR²)
WZ = √(41² - 25²)
WZ = 32.5
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