The velocity of the second ball after it was struck by the first ball is 3m/s.
Given the data in the question;
- Mass of ball 1; [tex]m = 10kg[/tex]
- Initial velocity of ball 1; [tex]u_1 = 13m/s[/tex]
- Final velocity of ball 1; [tex]v_1 = 7m/s[/tex]
- Mass 2; [tex]m = 20kg[/tex]
Since ball to was at rest
- Initial velocity of ball 2; [tex]u_2 = 0[/tex]
Final velocity of ball 2; [tex]v_2 =\ ?[/tex]
To determine the velocity of the second ball, we use conservation of linear momentum:
[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2[/tex]
We substitute our given values into the equation and solve for "[tex]v_2[/tex]"
[tex][10kg * 13m/s] + [ 20kg * 0] = [10kg * 7m/s] + [ 20kg * v_2] \\\\130kgm/s = 70kgm/s + [ 20kg * v_2]\\\\ 130kgm/s -70kgm/s = 20kg * v_2\\\\60kgm/s = 20kg * v_2\\\\v_2 = \frac{60kgm/s }{20kg} \\\\v_2 = 3m/s[/tex]
Therefore, the velocity of the second ball after it was struck by the first ball is 3m/s.
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