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An Oxygen Tank has a pressure of 1200. 0 Kpa at 283k. What will the pressure be if the temp. is increased to 378 K?

Respuesta :

Answer: (P2/P1)=(T2/T1)

(P2/1200.0kPa)=(387/283)

P2=(387K/283K) * (1200kPa)

P2= 1641kPa

Explanation:

An Oxygen Tank has a pressure of 1200 Kpa at 283K and when temp. is increased to 378 K then pressure will be 1,602.82 kpa.

How do we calculate the pressure?

From the ideal gas equation it is clear that pressure of gas is directly proportional to the temperature, and for this question required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = initial pressure of oxygen tank = 1200 kpa

T₁ = initial temperature of oxygen tank = 283 K

P₂ = final pressure of oxygen tank = ?

T₂ = final temperature of oxygen tank = 378 K

On putting values, we get

P₂ = (1200)(378) / (283) = 1,602.82 kpa

Hence resultant pressure of the oxygen tank is  1,602.82 kpa.

To know more about ideal gas equation, visit the below link:

https://brainly.com/question/555495

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