Answer:
(a) 0 (b) [tex]F=1.67\times 10^9\ N[/tex]
Explanation:
Given that,
Mass of a supertanker, [tex]m=1.7\times 10^8\ kg[/tex]
The engine of a generate a forward thrust of, [tex]F=7.4\times 10^5\ N[/tex]
(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :
F = ma, a is the acceleration
For constant velocity, a = 0
So, F = 0
(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.
F = mg
[tex]F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N[/tex]
Hence, this is the required solution.
