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A 1.20-L container contains 1.10 g of an unknown gas at STP. What is the molecular weight of the unknown gas?
A) 1.32 g/mole
B) 0.917 g/mole
C) 22.4 g/mole
D) 20.5 g/mole

Respuesta :

Neetoo

Answer:

M = 20.5 g/mol

Explanation:

Given data:

Volume of gas = 1.20 L

Mass of gas = 1.10 g

Temperature and pressure = standard

Solution:

First of all we will calculate the density.

Formula:

d = mass/ volume

d = 1.10 g/ 1.20 L

d = 0.92 g/L

Now we will calculate the molar  mass.

d = PM/RT

0.92 g/L = 1 atm × M / 0.0821 atm.L/mol.K ×273.15 K

M =  0.92 g/L × 0.0821 atm.L/mol.K ×273.15 K /  1 atm

M = 20.5 g/mol

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