The final temperature : 79.07°C
Further explanation
Heat transferred can be formulated
Q=m.c.ΔT
Q= heat, J
m=mass,g
c=specific heat, for water 4.18 J/g C
ΔT = temperature
Heat transferred : 130 kcal
1 kcal = 4186 J
130 kcal =
[tex]\tt 130\times 4186=544180~J[/tex]
mass = 2.5 kg =2500 g
t₁=27 °c
The final temperature :
[tex]\tt 544180=2500\times 4.18\times (t_2-27)\\\\t_2-27=52.07\\\\t_2=79.07^oC[/tex]
