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Write the full electronic configuration and draw the orbital box diagram of iron in its oxidation state in K3 Fe(CN)6. Hence determine the number of unpaired electrons in this state.

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Answer:

F[tex]e^{3t}[/tex]:1[tex]s^{2}[/tex][tex]2s^2[/tex]2[tex]p^{6}[/tex]3[tex]s^{2}[/tex]3[tex]p^{6}[/tex]3[tex]d^{5}[/tex]

3d: The orbital diagram of iron is 5 boxes with an up arrow inside

The number of unpaired electrons in this state is 5.  

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