Respuesta :

ardni313

The concentration of the acid solution : 0.43 M

Further explanation

Reaction

Cu + 2HCl ⇒ CuCl₂ + H₂

  • the amount of Cu reacting :

[tex]\tt 13.36-4.54=8.82~g[/tex]

  • mol Cu :(Ar=63.5 g/mol))

[tex]\tt \dfrac{8.82}{63.5}=0.139[/tex]

  • concentration of the acid solution(HCl) :

mol HCl :

[tex]\tt \dfrac{2}{1}\times 0.139=0.278[/tex]

concentration :

[tex]\tt M=\dfrac{mol}{V}=\dfrac{0.278}{0.65~L}=0.43[/tex]