Answer:
Height is 11.25m
Explanation:
Given the following data;
Initial velocity, u = 0
Final velocity, v = 15m/s
Acceleration due to gravity, g = 10m/s²
To find the height, we would use the third equation of motion;
[tex] V^{2} = U^{2} + 2aS [/tex]
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
- S represents the displacement (height) measured in meters.
[tex] V^{2} = U^{2} + 2aS [/tex]
Making S the subject, we have;
[tex] S = \frac {V^{2} - U^{2}}{2a}[/tex]
But a = g = 10m/s²
Substituting into the equation, we have;
[tex] S = \frac {15^{2} - 0^{2}}{2*10}[/tex]
[tex] S = \frac {225 - 0}{20}[/tex]
[tex] S = \frac {225}{20}[/tex]
S = 11.25m
Therefore, the ball will reach a height of 11.25m before it begins to fall.
