Answer:
The answer is "[tex]0.0199044586 \ m\\\\[/tex]".
Explanation:
The crucial stress essential for activating the spreading of the crack is [tex]\sigma[/tex], the hardness of the strain break is K, as well as the area long of a break is a, for dimensionless Y. Its equation of the length of its surface of the fracture is 50.1 MPa [tex]\sqrt{m}[/tex] on K, 200MPa on [tex]\sigma[/tex], and 1 on Y.
[tex]a = \frac{1}{\pi} (\frac{K}{Y \ \sigma} )^2 \\\\[/tex]
[tex]= \frac{1}{\pi} ( \frac{50.0}{1 \times 200} )^2 \\\\= \frac{1}{3.14} ( \frac{1}{4})^2 \\\\= \frac{1}{3.14} ( \frac{1}{16}) \\\\=\frac{1}{50.24}\\\\=0.0199044586 \ m\\\\[/tex]
