Answer:
$72
Step-by-step explanation:
Let t = Tires
Let O = Oil change
Given the following data;
Oil change, O = $47
Translating the word problem into an algebraic equation, we have;
4t + O = $335
Rearranging the equation, we have;
[tex] 4t = 335 - O[/tex]
Substituting the value of O;
[tex] 4t = 335 - 47[/tex]
[tex] 4t = 288[/tex]
[tex] t = \frac {288}{4}[/tex]
t = 72
Therefore, the cost of each tire is $72.