Answer:
[tex]\rho=7373.2g/cm^3[/tex]
Explanation:
Hello!
In this case, since the density is defined as the degree of compactness of a substance, and is defined as the mass over the volume:
[tex]\rho= \frac{m}{V}[/tex]
Given the dimensions of the bar of lead, we can compute the volume as shown below:
[tex]V=2.00cm*3.00cm*1.00in*\frac{1in}{2.54cm} \\\\V=2.36cm^3[/tex]
Thus, the density turns out:
[tex]\rho=\frac{173g}{2.36cm^3} \\\\\rho=7373.2g/cm^3[/tex]
Best regards!
